java – 使用Gson将JSON映射到POJO

我有以下JSON来表示salt请求的服务器响应:

{
    "USER":
    {
        "E_MAIL":"email",
        "SALT":"salt"
    },
    "CODE":"010"
}

我试图用以下POJO映射它:

public class SaltPOJO {
    private String code = null;
    private User user = null;

    @Override
    public String toString() {
        return this.user.toString();
    }

    public String getCode() {
        return code;
    }
    public void setCode(String code) {
        this.code = code;
    }
    public User getUser() {
        return user;
    }
    public void setUser(User user) {
        this.user = user;
    }

    public class User {
        private String e_mail = null;
        private String salt = null;

        @Override
        public String toString() {
            return this.e_mail + ": " + this.salt;
        }
        public String getE_mail() {
            return e_mail;
        }
        public void setE_mail(String e_mail) {
            this.e_mail = e_mail;
        }
        public String getSalt() {
            return salt;
        }
        public void setSalt(String salt) {
            this.salt = salt;
        }
    }
}

现在我每次都这样做:

Gson gson = new Gson();
SaltPOJO saltPojo = gson.fromJson(json.toString(), SaltPOJO.class);

Log.v("Bla", saltPojo.toString());

saltPojo.toString()为null.如何使用Gson将我的JSON映射到POJO?
我的变量的顺序对于Gson映射是否重要?

最佳答案

Is the order of my variables important for the Gson mapping?

不,事实并非如此.

How can i map my JSON into POJO using Gson?

它是区分大小写的,JSON字符串中的键应该与POJO类中使用的变量名相同.

您可以使用@SerializedName注释来使用任何变量名称.

示例代码:

  class SaltPOJO {
        @SerializedName("CODE")
        private String code = null;
        @SerializedName("USER")
        private User user = null;
        ...

        class User {
            @SerializedName("E_MAIL")
            private String e_mail = null;
            @SerializedName("SALT")
            private String salt = null;

转载注明原文:java – 使用Gson将JSON映射到POJO - 代码日志