如何使用fread和fwrite函数来读写二进制文件?

嗨,在我的项目中,我必须读取一个.bin文件,它具有短(16位值)形式的传感器数据.我正在使用fread函数进入缓冲区,但我觉得读入不正确.我的意思是我的写作和我读到的内容之间没有一致性,你们可以建议这里有什么问题吗?这不是我的项目代码…我只是在这里验证fread和fwrite函数.

#include<stdio.h>
void main()
{
    FILE *fp = NULL;

    short x[10] = {1,2,3,4,5,6,5000,6,-10,11};
    short result[10];

    fp=fopen("c:\\temp.bin", "wb");

    if(fp != NULL)
    {
        fwrite(x, 2 /*sizeof(short)*/, 10 /*20/2*/, fp);
        rewind(fp);
        fread(result, 2 /*sizeof(short)*/, 10 /*20/2*/, fp);
    }
    else
        exit(0);

    printf("\nResult");
    printf("\n%d",result[0]);
    printf("\n%d",result[1]);
    printf("\n%d",result[2]);
    printf("\n%d",result[3]);
    printf("\n%d",result[4]);
    printf("\n%d",result[5]);
    printf("\n%d",result[6]);
    printf("\n%d",result[7]);
    printf("\n%d",result[8]);
    printf("\n%d",result[9]);

    fclose(fp)
 }

之后我做了fread()(HEX值):

temp.bin:
01 02 03 04 05 06 e1 8e 88 06 ef bf b6 0b...

我做了fwrite()

stdout:
Result
0
914
-28
-28714
-32557
1
512
-32557
908
914
最佳答案
用模式w(读写)打开文件.以下代码工作:

#include<stdio.h>
int main()
{
    FILE *fp = NULL;

    short x[10] = {1,2,3,4,5,6,5000,6,-10,11};
    short result[10];
    int i;

    fp=fopen("temp.bin", "w+");

    if(fp != NULL)
    {
        fwrite(x, sizeof(short), 10 /*20/2*/, fp);
        rewind(fp);
        fread(result, sizeof(short), 10 /*20/2*/, fp);
    }
    else
        return 1;

    printf("Result\n");
    for (i = 0; i < 10; i++)
        printf("%d = %d\n", i, (int)result[i]);

    fclose(fp);
    return 0;
}

输出:

Result
0 = 1
1 = 2
2 = 3
3 = 4
4 = 5
5 = 6
6 = 5000
7 = 6
8 = -10
9 = 11

转载注明原文:如何使用fread和fwrite函数来读写二进制文件? - 代码日志