python – 从Celery中的’task_id’中检索未知任务的结果

如果我以前不知道执行了哪个任务,如何提取任务结果?
这是设置:
给定以下源(‘tasks.py’):

from celery import Celery

app = Celery('tasks', backend="db+mysql://u:p@localhost/db", broker = 'amqp://guest:guest@localhost:5672//')

@app.task
def add(x,y):
   return x + y


@app.task
def mul(x,y):
   return x * y

RabbitMQ 3.3.2在本地运行:

marcs-mbp:sbin marcstreeter$./rabbitmq-server

              RabbitMQ 3.3.2. Copyright (C) 2007-2014 GoPivotal, Inc.
  ##  ##      Licensed under the MPL.  See http://www.rabbitmq.com/
  ##  ##
  ##########  Logs: /usr/local/var/log/rabbitmq/rabbit@localhost.log
  ######  ##        /usr/local/var/log/rabbitmq/rabbit@localhost-sasl.log
  ##########
              Starting broker... completed with 10 plugins.

与Celery 3.1.12在本地运行:

 -------------- celery@Marcs-MacBook-Pro.local v3.1.12 (Cipater)
---- **** -----
--- * ***  * -- Darwin-13.2.0-x86_64-i386-64bit
-- * - **** ---
- ** ---------- [config]
- ** ---------- .> app:         tasks:0x105dea3d0
- ** ---------- .> transport:   amqp://guest:**@localhost:5672//
- ** ---------- .> results:     disabled
- *** --- * --- .> concurrency: 8 (prefork)
-- ******* ----
--- ***** ----- [queues]
 -------------- .> celery           exchange=celery(direct) key=celery

然后我可以导入方法并使用’task_id’检索结果:

from tasks import add, mul
from celery.result import AsyncResult

result = add.delay(2,2)
task_id = result.task_id
result.get() # 4

result = AsyncResult(id=task_id)
result.get() # 4

result = add.AsyncResult(id=task_id)
result.get() # 4

# and the same for the 'mul' task. Just imagine I put it here

在下一个示例中,我将在流程之间拆分这些步骤.在一个过程中,我像这样检索’task_id’:

from tasks import add

result = add.delay(5,5)
task_id = result.task_id

在另一个过程中,如果我使用相同的’task_id'(复制并粘贴到另一个REPL,或在不同的HTTP请求中),如下所示:

from celery.result import AsyncResult

result = AsyncResult(id="copied_task_id", backend="db+mysql://u:p@localhost/db")
result.get() # AttributeError: 'str' object has no attribute 'get_task_meta'
result.state # AttributeError: 'str' object has no attribute 'get_task_meta'
result.status # AttributeError: 'str' object has no attribute 'get_task_meta'

在另一个过程中,如果我这样做:

from task import add # in this instance I know that an add task was performed

result = add.AsyncResult(id="copied_task_id")
result.status # "SUCCESSFUL"
result.state # "SUCCESSFUL"
result.get() # 10

我希望能够在不知道什么任务产生结果的情况下获得结果.在我的真实环境中,我计划将此task_id返回给客户端,让他们通过HTTP请求查询其作业的状态.

最佳答案
好的 – 所以我一直在寻找解决方案很长一段时间,现在我终于正式发布了这个并查看了documentation我找到了this gem

class celery.result.AsyncResult(id, backend=None, task_name=None,
app=None, parent=None)

Query task state.

Parameters:

id – see 07002.

backend – see 07003.

  
  异常TimeoutError
  
  

Error raised for timeouts.

  
  AsyncResult.app =无

因此,不是提供后端参数,而是提供“app”参数,而不是这样:

from celery.result import AsyncResult
from task import app

# Assuming add.delay(10,10) was called in another process
# and that I'm using a 'task_id' I retrieved from that process

result = AsyncResult(id='copied_task_id', app=app)
result.state # 'SUCCESSFUL'
result.get() # 20

这对很多人来说可能是显而易见这不是我.现在我可以说的是,这个解决方案“只是有效”,但如果我知道它是受制裁的方式,我会觉得更舒服.如果您知道文档中的一个部分使其更清晰,请将其发布在评论中或作为答案,如果可以,我会选择它作为答案.

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