java – 使用JPA持久保存到数据库中的密钥“PRIMARY”的重复条目

我有一个错误,JPA持久存在我的数据库中,当我将第二个文件持久存储到数据库时发生错误.我需要导入大量数据集,每个数据集有5张.即使某些相同的数据已经存在,也需要更新每个表.目前我收到以下错误

错误

17:26:35,315 WARN  [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (http-localhost-127.0.0.1-8080-1) SQL Error: 1062, SQLState: 23000
17:26:35,316 ERROR [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (http-localhost-127.0.0.1-8080-1) Duplicate entry '0' for key 'PRIMARY'

数据库脚本

我创建数据库的脚本如下：

CREATE DATABASE IF NOT EXISTS sampleDB;



use sampleDB;



CREATE TABLE IF NOT EXISTS `Table1`(`mcc` int(10) NOT NULL,`mnc` int(10) NOT NULL,`operator` varchar(50) DEFAULT NULL,`country` varchar(50) DEFAULT NULL,

    PRIMARY KEY (`mcc`,`mnc`))ENGINE=InnoDB;



CREATE TABLE IF NOT EXISTS `Table2`(`tac` int(10) NOT NULL,`marketingName` varchar(50) DEFAULT NULL,`manufacturer` varchar(50) DEFAULT NULL,

    `accessCapability` varchar(200) DEFAULT NULL,`model` varchar(50) DEFAULT NULL,`vendorName` varchar(50) DEFAULT NULL,

    `ueType` varchar(20) DEFAULT NULL,`os` varchar(20) DEFAULT NULL,`inputMode` varchar(20) DEFAULT NULL,PRIMARY KEY (`tac`))ENGINE=InnoDB;



CREATE TABLE IF NOT EXISTS `Table3`(`causeClass` varchar(10) NOT NULL,`description` varchar(255) NOT NULL,PRIMARY KEY (`causeClass`))ENGINE=InnoDB;



CREATE TABLE IF NOT EXISTS `Table4`(`causeCode` int(5) NOT NULL,`eventId` int(5) NOT NULL,`description` varchar(255) DEFAULT NULL,

    PRIMARY KEY (`causeCode`,`eventId`) ON UPDATE NO ACTION))ENGINE=InnoDB;



CREATE TABLE IF NOT EXISTS `Table5`(`baseDataTableId` int(11) NOT NULL AUTO_INCREMENT,`dateTime` DATETIME NOT NULL,`eventId` int(5) NOT NULL,`causeClass` varchar(10) NOT NULL,

  `ueType` int(15) NOT NULL,`market` int(10) NOT NULL,`operator` int(10) NOT NULL,`cellId` tinyint(2) DEFAULT NULL,`duration` smallint(7) DEFAULT NULL,

  `causeCode` int(5) NOT NULL,`neVersion` varchar(7) DEFAULT NULL,`imsi` varchar(255) DEFAULT NULL,`hier3Id` varchar(255) DEFAULT NULL,`hier32Id` varchar(255) DEFAULT NULL,

  `hier321Id` varchar(255) DEFAULT NULL,PRIMARY KEY (`baseDataTableId`))ENGINE=InnoDB;

Java Hibernate属性

我的Hibernate属性如下：

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
   xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="
        http://java.sun.com/xml/ns/persistence
        http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
   <persistence-unit name="primary">
      <jta-data-source>java:jboss/datasources/MySqlDS</jta-data-source>
      <properties>
         <!-- Properties for Hibernate -->
         <property name="hibernate.hbm2ddl.auto" value="update" />
         <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
         <property name="hibernate.show_sql" value="false" />
         <property name="hibernate.format_sql" value="false" />
      </properties>
   </persistence-unit>
</persistence>

Java的

实体类示例：

@Entity
@Table(name = "Table3")
public class Table3 {

        @Id
        private int causeClass;
        private String description;

        public Table3(){}

        public Table3(int causeClass, String description) {
            super();
            this.causeClass = causeClass;
            this.description = description;
        }

        // getters & setters

}

任何想法如何解决这个问题？

最佳答案

确保使用良好的EntityManager方法更新现有实体.您似乎尝试执行持久操作而不是现有实体的合并.
当持久化antity时,尝试捕获EntityExistsException或PersistenceException,并在catch块中调用merge方法.
例如：

save(Enity item){
    try{
        //Try to insert your entity by calling persist method    
    }
    catch(EntityExistsException e){
        //Entity you are trying to insert already exist, then call merge method
    }
}