单元测试 – 单元测试Angular 2 authGuard;间谍方法没有被调用

我正在尝试对我的auth警卫服务进行单元测试.从this answer开始,我能够做到这一点,但现在当我为此进行单元测试时,它表示预期的间谍导航已被调用.

如何让我的间谍路由器在服务中用作this.router?

AUTH-guard.service.ts

import { Injectable } from '@angular/core';
import { Router, CanActivate } from '@angular/router';

@Injectable()
export class AuthGuardService {

  constructor(private router:Router) { }

  public canActivate() {
    const authToken = localStorage.getItem('auth-token');
    const tokenExp = localStorage.getItem('auth-token-exp');
    const hasAuth = (authToken && tokenExp);

    if(hasAuth && Date.now() < +tokenExp){
      return true;
    }
    this.router.navigate(['/login']);
    return false;
  }
}

AUTH-guard.service.spec.ts

import { TestBed, async, inject } from '@angular/core/testing';
import { RouterTestingModule } from '@angular/router/testing';

import { AuthGuardService } from './auth-guard.service';

describe('AuthGuardService', () => {
  let service:AuthGuardService = null;
  let router = {
    navigate: jasmine.createSpy('navigate')
  };

  beforeEach(() => {
    TestBed.configureTestingModule({
      providers: [
        AuthGuardService,
        {provide:RouterTestingModule, useValue:router}
      ],
      imports: [RouterTestingModule]
    });
  });

  beforeEach(inject([AuthGuardService], (agService:AuthGuardService) => {
    service = agService;
  }));

  it('checks if a user is valid', () => {
    expect(service.canActivate()).toBeFalsy();
    expect(router.navigate).toHaveBeenCalled();
  });
});

将RouterTestingModule替换为Router,如示例中所示,回答抛出模块’DynamicTestModule’导入的意外值’undefined’.

最佳答案
而不是存根路由器,在router.navigate()方法上使用依赖注入和间谍:

import { TestBed, async, inject } from '@angular/core/testing';
import { RouterTestingModule } from '@angular/router/testing';
import { Router } from '@angular/router';

import { AuthGuardService } from './auth-guard.service';

describe('AuthGuardService', () => {

  beforeEach(() => {
    TestBed.configureTestingModule({
      providers: [AuthGuardService],
      imports: [RouterTestingModule]
    });
  });

  it('checks if a user is valid',

    // inject your guard service AND Router
    async(inject([AuthGuardService, Router], (auth, router) => {

      // add a spy
      spyOn(router, 'navigate');

      expect(auth.canActivate()).toBeFalsy();
      expect(router.navigate).toHaveBeenCalled();
    })
  ));
});

https://plnkr.co/edit/GNjeJSQJkoelIa9AqqPp?p=preview

转载注明原文:单元测试 – 单元测试Angular 2 authGuard;间谍方法没有被调用 - 代码日志