linux – grep完全单词匹配(-w)不适用于文本文件中的文件路径

我试图在文件中grep一个带有完整路径的文件名,其中包含’ls -l’输出,但它无法正确匹配.

执行字符串搜索的shell脚本中的行

pcline=`grep -w "$file1" $file2` # grep for file1 in file2 contents

如果我回显命令,命令的输出如下所示

grep -w run /home/rajesh/rootfs.layout

Expected
lrwxrwxrwx 1 root root 3 Aug 28 run

Actual
lrwxrwxrwx 1 root root 7 Aug 28 bin/run-parts
lrwxrwxrwx 1 root root 3 Aug 28 run
-rwxr-xr-x 1 root root 303 Aug 28 tests/aes/run.sh
-rwxr-xr-x 1 root root 445 Aug 28 tests/auto_ui/run.sh
-rwxr-xr-x 1 root root 320 Aug 28 tests/available_memory/run.sh
-rwxr-xr-x 1 root root 308 Aug 28 tests/fonts/run.sh
-rwxr-xr-x 1 root root 309 Aug 28 tests/html_config_page/run.sh
-rwxr-xr-x 1 root root 361 Aug 28 tests/ipc/run.sh
-rwxr-xr-x 1 root root 304 Aug 28 tests/JSON/run.sh
-rwxr-xr-x 1 root root 303 Aug 28 tests/log4cplus_cpp/run.sh
-rwxr-xr-x 1 root root 301 Aug 28 tests/log4cplus_c/run.sh
-rwxr-xr-x 1 root root 751 Aug 28 tests/msm_basic/run.sh
-rwxr-xr-x 1 root root 472 Aug 28 tests/res_man_dependency/run.sh
-rwxr-xr-x 1 root root 465 Aug 28 tests/res_man_ipc/run.sh
-rwxr-xr-x 1 root root 789 Aug 28 tests/res_man_multi_process/run.sh
-rwxr-xr-x 1 root root 469 Aug 28 tests/res_man_private_client/run.sh
-rwxr-xr-x 1 root root 492 Aug 28 tests/res_man_public_client/run.sh
-rwxr-xr-x 1 root root 311 Aug 28 tests/virt_mem_config/run.sh
lrwxrwxrwx 1 root root 6 Aug 28 var/run]

我尝试的技巧是添加一个空白,这在我的输入文件中得到保证,这在控制台中有效,但在分配给变量时则不行.

grep " tests/aes/run.sh" /home/rajesh/rootfs.layout

在脚本中排队

pcline=`grep \"" $file1"\" $file2`     # grep for file1 in file2 contents

如果我在此脚本中犯了任何错误,请告诉我.

最佳答案
你可以像这样使用egrep:

egrep "(^| )$file1( |$)" "$file2"

如果file1 =“run”,则上面的命令将匹配以行开头或空格开头的字符串运行,后跟空格或行结束.

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