Python:用另一个数组元素作为键对数组进行排序?

import numpy as np
x = np.array(range(10 * 30)).reshape(100, 3)
y = np.array(range(1010, 10, -10))
res = sorted(x, key = lambda y:y) #ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
res = sorted(x, key=y) #TypeError: 'tuple' object is not callable
最佳答案
尝试argsort:

import numpy as np
x = np.array(range(10 * 30)).reshape(100, 3)
y = np.array(range(1010, 10, -10))
args = y.argsort(axis = 0)
print x[args]

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