java – Spring:url无法正确解析链接

虽然我对Java很有经验,但我对Spring框架和Web应用程序都很陌生.当我在本地tomcat服务器上运行我的站点时,URL为:http:// localhost:8080 / myApp /

现在请求映射将我委托给我的主页:

@RequestMapping(value = "/", method = RequestMethod.GET)
public String someMethod(Model model) { ... 
   return "index"; }

现在在index.xhtml文件中,我使用< a href =“apps /”> link< / a>链接到另一个页面
但当我想链接回索引页面时,我必须使用< a href =“../ index /”> link< / a>.我搜索了一个解决方案,发现:

<spring:url value='/apps' var="apps_url" />
<a href="${apps_url}">link</a>

但是spring:url总是解析为http:// localhost:8080 / myApp / – 我目前所在的页面.另外,当我只使用这样的链接:< a href =“/ otherSite”> link< / a>时,它总是解析为http:// localhost:8080 / otherSite而不是http:// localhost: 8080 / myApp / otherSite就像我预期的那样.如何让我的链接工作?是http:// localhost:8080 / myApp隐式定义为我的上下文还是可以/应该更改为http:// localhost:8080 /?

此外,本地tomcat服务器上的URL与Web应用程序发布时的URL之间是否存在任何连接?

以下是我的一些应用程序文件:

servlet的context.xml中:

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->

    <!-- Enables the Spring MVC @Controller programming model -->
    <annotation-driven />

    <context:component-scan base-package="myApp" />

    <tx:annotation-driven transaction-manager="transactionManager"/>

    <!-- Handles HTTP GET requests for /resources/** and /css/** by efficiently 
    serving up static resources in the ${webappRoot}/resources directory -->
    <resources mapping="/resources/**" location="/resources/" />
    <resources mapping="/css/**" location="/css/" />

    <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <beans:property name="prefix" value="/WEB-INF/views/" />
        <beans:property name="suffix" value=".xhtml" />
    </beans:bean>

</beans:beans>

摘自web.xml:

<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>

<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<!-- Processes application requests -->

<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>
最佳答案
最好将所有链接放在下面

<a href="${pageContext.servletContext.contextPath}/othersite"> Other site </a>

${pageContext.servletContext.contextPath}始终为您的应用程序提供root权限,当您开发使用http:// localhost:8080 / myApp时,您的应用程序root是/ myapp,但是当您希望将应用程序置于生产环境中时通常是您的应用程序root将是/,在链接之前使用${pageContext.servletContext.contextPath}确保它在两种情况下都能正常工作

转载注明原文:java – Spring:url无法正确解析链接 - 代码日志