Python使用re模块来解析导入的文本文件

def regexread():
    import re

    result = ''
    savefileagain = open('sliceeverfile3.txt','w')

    #text=open('emeverslicefile4.txt','r')
    text='09,11,14,34,44,10,11,  27886637,    0\n561, Tue, 5,Feb,2013, 06,25,31,40,45,06,07,  19070109,    0\n560, Fri, 1,Feb,2013, 05,21,34,37,38,01,06,  13063500,    0\n559, Tue,29,Jan,2013,'

    pattern='\d\d,\d\d,\d\d,\d\d,\d\d,\d\d,\d\d'
    #with open('emeverslicefile4.txt') as text:     
    f = re.findall(pattern,text)

    for item in f:
        print(item)

    savefileagain.write(item)
    #savefileagain.close()

上面写的函数解析文本并返回七个数字的集合.我有三个问题.

>首先,包含与text = ’09,…等完全相同的文本的’read’文件返回一个TypeError期望的字符串或缓冲区,即使阅读了一些帖子也无法解决.
>其次,当我尝试将结果写入’write’文件时,不返回任何内容
>第三,我不知道如何获得与print语句相同的输出,这是三行七个数字,这是我想要的输出.

这是我第一次使用正则表达式,所以请温柔!

最佳答案
这应该做的伎俩,检查评论以解释我在这里做什么=)
祝好运

import re
filename = 'sliceeverfile3.txt'
pattern  = '\d\d,\d\d,\d\d,\d\d,\d\d,\d\d,\d\d'
new_file = []

# Make sure file gets closed after being iterated
with open(filename, 'r') as f:
   # Read the file contents and generate a list with each line
   lines = f.readlines()

# Iterate each line
for line in lines:

    # Regex applied to each line 
    match = re.search(pattern, line)
    if match:
        # Make sure to add \n to display correctly when we write it back
        new_line = match.group() + '\n'
        print new_line
        new_file.append(new_line)

with open(filename, 'w') as f:
     # go to start of file
     f.seek(0)
     # actually write the lines
     f.writelines(new_file)

转载注明原文:Python使用re模块来解析导入的文本文件 - 代码日志