我有一个名为private_messages的SQL表,其中包含字段(id,from,to,message,stamp).
戳记字段对应于消息的日期
戳记字段对应于消息的日期
那么我需要什么查询:
1)在两个用户之间进行对话(按日期排序)?
我试过了这个问题
(SELECT * FROM private_messages WHERE from=$my_id AND to=$other_id)
UNION
(SELECT * FROM private_messages WHERE from=$other_id AND to=$my_id)
ORDER BY stamp
;
但不起作用……
2)获取我和其他用户之间的最后一条消息,每个用户都有不同的用户,按日期排序(例如构建一个像faceebook这样的收件箱)?
最佳答案
1.)
SELECT *
FROM private_messages a
WHERE (a.from = $my_id AND a.to = $other_id) OR
(a.from = $other_id AND a.to = $my_id)
ORDER BY stamp DESC
2.)
SELECT f.*
FROM
(
SELECT *
FROM private_messages a
WHERE (LEAST(a.from, a.to), GREATEST(a.from, a.to), a.stamp)
IN (
SELECT LEAST(b.from, b.to) AS x,
GREATEST(b.from, b.to) AS y,
MAX(b.stamp) AS msg_time
FROM private_messages b
GROUP BY x, y
)
) f
WHERE $my_id IN (f.from, f.to)
ORDER BY f.stamp DESC
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转载注明原文:php – MySQL在两个用户之间进行对话 - 代码日志