php – MySQL在两个用户之间进行对话

我有一个名为private_messages的SQL表,其中包含字段(id,from,to,message,stamp).
戳记字段对应于消息的日期

那么我需要什么查询：

1)在两个用户之间进行对话(按日期排序)？

我试过了这个问题

(SELECT * FROM private_messages WHERE from=$my_id AND to=$other_id) 
UNION 
(SELECT * FROM private_messages WHERE from=$other_id AND to=$my_id) 
ORDER BY stamp
;

但不起作用……

2)获取我和其他用户之间的最后一条消息,每个用户都有不同的用户,按日期排序(例如构建一个像faceebook这样的收件箱)？

最佳答案

1.)

SELECT  * 
FROM    private_messages a
WHERE   (a.from = $my_id AND a.to = $other_id) OR
        (a.from = $other_id AND a.to = $my_id)
ORDER   BY stamp DESC

2.)

SELECT  f.*
FROM
        (
            SELECT  *
            FROM    private_messages a
            WHERE  (LEAST(a.from, a.to), GREATEST(a.from, a.to), a.stamp) 
                    IN  (   
                            SELECT  LEAST(b.from, b.to) AS x, 
                                    GREATEST(b.from, b.to) AS y,
                                    MAX(b.stamp) AS msg_time
                            FROM    private_messages b
                            GROUP   BY x, y
                        )
        ) f
WHERE   $my_id IN (f.from, f.to)
ORDER   BY f.stamp DESC

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