在C中输出ascii表

码:

#include <iostream>
#include <iomanip>
using namespace std;

class Ascii_output {
public:
    void run() {
        print_ascii();
    }
private:
    void print_ascii() {
        int i, j;                                                           // i is         used to print the first element of each row
                                                                        // j is used to print subsequent columns of a given row
    char ch;                                                            // ch stores the character which is to be printed
    cout << left;

    for (i = 32; i < 64; i++) {                                         // 33 rows are printed out (64-32+1)
        ch = i;
        if (ch != '\n')                                                 // replaces any newline printouts with a blank character
            cout << setw(3) << i << " " << setw(6) << ch;
        else
            cout << setw(3) << i << " " << setw(6);

        for (j = 1; j < 7; j++) {                                       // decides the amount of columns to be printed out, "j < 7" dictates this
            ch += 32*j;                                                 // offsets the column by a multiple of 32
            if (ch != '\n')                                             // replaces any newline printouts with a blank character
                cout << setw(3) << i+(32*j) << " " << setw(6) << ch;
            else
                cout << setw(3) << i+(32*j) << " " << setw(6);
        }

        cout << endl;
    }
    }
};

输出:

为什么我没有得到正确的缩进输出和值为96 – 255的奇怪字符?

最佳答案
这条线做得不对:

ch += 32*j;

你想要数32,那就是

ch += 32;

要么

ch = i + 32*j;

我强烈建议您在输出期间使数字和字符值匹配.所以改变

cout << setw(3) << i+(32*j) << " " << setw(6) << ch;

cout << setw(3) << int(ch) << " " << setw(6) << ch;

转载注明原文:在C中输出ascii表 - 代码日志