mysql – 具有3个表的复杂IF语句

这是this question from yesterday的延续.

这是我的三个表:

战士表

fighter_id |  name
-----------------------
1          | John
2          | Steve
3          | Bill
4          | Bobby

事件表

event_id  |  event_name  |  event_date
-------------------------------------------
1          | MMA         |  01/01/2010
2          | Cool        |  02/20/2010
3          | Yeaa!       |  04/15/2010

战斗表

fight_id  |  fighter_a  |  fighter_b  |  winner  |  method  |  event
-----------------------------------------------------------------------
1         | 1           |  2          |  1       | Sub      | 1
2         | 4           |  1          |  4       | KO       | 2
3         | 1           |  3          |  NULL    | Draw     | 3

结果试图得到

result  |  opponent  |  method  |  event  |  date        
----------------------------------------------------------
Draw    | Bill       |  Draw    |  Yeaa!  |  04/15/2010  
Loss    | Bobby      |  KO      |  Cool   |  02/20/2010 
Win     | Steve      |  Sub     |  MMA    |  01/01/2010

所以在战斗表中,fighter_a,fighter_b和winner是与Fighters表中的fighter_id相对应的整数.

我基本上在一个基于fighter_id($fighter_id)检索数据的页面上.

我正在尝试用该战斗机的每次战斗创建行,包括他的对手的名字,结果(胜利,失败,平局或者nc),方法,event_name和event_date.挑战在于胜利者可以是战士_或战士.它并不总是在同一列中.我感谢任何帮助.

select 
    fight_id,
    CASE
      WHEN winner is not null and winner=fighter_id then 'win'
      WHEN winner is not null and winner<>fighter_id then 'loss'
      WHEN winner is null and method='Draw' then 'draw'
      WHEN winner is null and method = 'No Contest' then 'no contest'
      ELSE ''
    END as match_result,
    participant.name 'participant',
    opponent.name 'opponent'
FROM fights
    INNER JOIN fighters as participant on participant.fighter_id = fights.fighter_a
    INNER JOIN fighters as oppoent on opponent.fighter_id = fights.fighter_b
WHERE 
    fighter_a=$fighter_id OR fighter_b=$fighter_id
ORDER BY
    event_date DESC
最佳答案
使用带有条件的subselect将你要查找的fighter_id切换到column_a,如果它在column_b中,这样就简化了你的操作并加入了外部查询:

SELECT
    (
        CASE
            WHEN a.winner = a.f_a THEN 'Win'
            WHEN a.winner = a.f_b THEN 'Loss'
            WHEN a.winner IS NULL THEN a.method
        END
    ) AS result,
    b.name AS opponent,
    a.method AS method,
    c.event_name AS event,
    c.event_date AS date
FROM
    (
        SELECT 
            IF(fighter_b = $fighter_id, fighter_b, fighter_a) AS f_a,
            IF(fighter_b = $fighter_id, fighter_a, fighter_b) AS f_b,
            winner,
            method,
            event
        FROM 
            fights
        WHERE
            $fighter_id IN (fighter_a, fighter_b)
    ) a
INNER JOIN
    fighters b ON a.f_b = b.fighter_id
INNER JOIN
    events c ON a.event = c.event_id
ORDER BY
    c.event_date DESC

此外,如果获胜者字段为空,则只需回显方法字段.这样,当您想要添加另一种类型的方法,其中wins对您的系统为null时,您不必继续对CASE语句进行更多条件检查.

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